# Zinc weighing 6.5 kg was treated with 120 kg of 10% sulfuric acid solution. Determine the amount of gas

August 30, 2021 | education

| **Zinc weighing 6.5 kg was treated with 120 kg of 10% sulfuric acid solution. Determine the amount of gas evolved if the yield of this reaction product is 80% of the theoretically possible.**

Given:

m (Zn) = 6.5 kg = 6500 g

m solution (H2SO4) = 120 kg = 120,000 g

ω (H2SO4) = 10%

η (gas) = 80%

Find:

V (gas) -?

Solution:

1) Zn + H2SO4 => ZnSO4 + H2 ↑;

2) n (Zn) = m (Zn) / M (Zn) = 6500/65 = 100 mol;

3) m (H2SO4) = ω (H2SO4) * m solution (H2SO4) / 100% = 10% * 120,000 / 100% = 12,000 g;

4) n (H2SO4) = m (H2SO4) / M (H2SO4) = 12000/98 = 122.45 mol;

5) n theory. (H2) = n (Zn) = 100 mol;

6) n practical (H2) = η (H2) * n theore. (H2) / 100% = 80% * 100/100% = 80 mol;

7) V (H2) = n (H2) * Vm = 80 * 22.4 = 1792 hp

Answer: The volume of H2 is 1792 liters.

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