АС – diameter with center О, angle AOB = 124 degrees. Determine the angles of the BOC triangle

The angles AOB and COB are adjacent, the sum of which is 180, then the angle COB = (180 – AOB) = (180 – 124) = 56.

The triangle BОС is isosceles, since the segments ОB and ОB are the radii of the circle, then the angle ОBС = ОСB = (180 – СОВ) / 2 = (180 – 56) / 2 = 62.

Answer: The angles of the BOC triangle are 56, 62, 62.



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