0.02 kg of carbon dioxide is heated at constant volume. Determine the change in the internal energy

0.02 kg of carbon dioxide is heated at constant volume. Determine the change in the internal energy of a gas when heated from 20 to 108 degrees Celsius (Cv = 655J / kg * K)

Problem solutions:

From the condition, it can be understood that the work of the gas is zero, because the volume of the gas is constant. Therefore, this is an isochoric process, i.e. ΔU = Q.

Therefore, ΔU = c * m * (tк – tн).

Knowing the formula, we find the change in internal energy,

ΔU = 655 * 0.02 * (108 – 20) = 655 * 0.02 * 88 = 1152.8 (J).

Answer: 1152.8 (J).