0.2 mol of butane burned out. How much g of CO2 was formed during this.

univerkov | September 7, 2021 | education

Butane combustion reaction equation:

2C4H10 + 13O2 = 8CO2 + 10H2O

According to the reaction equation, 8 mol of CO2 is formed per 2 mol of C4H10, therefore:

v (CO2) = v (C4H10) * 8/2 = 0.2 * 8/2 = 0.8 (mol).

Thus, the mass of the resulting carbon dioxide:

m (CO2) = v (CO2) * M (CO2) = 0.8 * 44 = 35.2 (g).

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