0.3 gasoline was poured from the container, 0.6 more from the remaining.

0.3 gasoline was poured from the container, 0.6 more from the remaining. The rest weighed 5.88 tons. how much gasoline was there originally?

To solve the problem, an equation can be drawn up, since it is known that first 0.3 parts of gasoline were poured from the container, then 0.6 of the remaining, and 5.88 tons remained in the container.

Let’s denote by x the initial amount of gasoline in the tank:

x – 0.3x – (x – 0.3) * 0.6 = 5.88;

x – 0.3x – 0.6x + 0.18 = 5.88;

0.1x = 5.7;

x = 57 tons.

Answer: Initially, the tank contained 57 tons of gasoline.