0.36 g of metal combined with 168 ml of oxygen. Determine the equivalence of the metal.

univerkov | May 21, 2021 | education

m = 0.36 g – metal
v = 168 ml = 0.168 l – oxygen
v (eqO₂) = v₀ / z
v₀ = 22.4 l / mol
z = 2 * 2 = 4 equivalence number

m / M (eq) = v / v (eqO₂) = vz / v₀

M (eq) = mv₀ / {vz}
M (eq) = 0.36 * 22.4 / {0.168 * 4} = 12 g-eq / mol

metal equivalence is 12 g / mol

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