0.5 dm3 of water was poured into a large beaker, and 150 ml into a small one. How much is the water

0.5 dm3 of water was poured into a large beaker, and 150 ml into a small one. How much is the water level in one beaker higher than the level in the other, if the bottom area of the small beaker is 8 cm2, and the large one is 25 cm2?

Given:

V1 = 0.5 cubic decimeters = 0.0005 cubic meters – the volume of water poured into a large beaker;

s1 = 8 square centimeters = 0.0008 square meters is the bottom area of ​​a large beaker;

V2 = 150 ml = 0.150 cubic decimeters = 0.00015 cubic meters – the volume of water poured into a small beaker;

s2 = 25 square centimeters = 0.0025 square meters is the bottom area of ​​a small beaker.

It is required to determine how much the water level in one beaker is higher than in another.

The water level in the large beaker is:

h1 = V1 / s1 = 0.0005 / 0.0008 = 0.625 meters.

The water level in a small beaker is:

h2 = V2 / s2 = 0.00015 / 0.0025 = 0.06 meters.

Then:

h1 – h1 = 0.625 – 0.06 = 0.565 meters.

Answer: The water level in the large beaker is 0.565 meters higher.