0.5 liters of water was poured into an aluminum pan weighing 500 g at a temperature of 20 degrees.

0.5 liters of water was poured into an aluminum pan weighing 500 g at a temperature of 20 degrees. How much heat must be brought to a pot of water to boil the water? Disregard heat exchange with the environment.

Data: m1 (weight of the aluminum pan) = 500 g (0.5 kg); V2 (volume of water poured into the pan) = 0.5 l (0.5 * 10-3 m3); t0 (initial temperature of water and pot) = 20 ºС.

Constants: ρw (water density) = 1000 kg / m3; Ca (specific heat capacity of aluminum) = 920 J / (kg * ºС); Sv (specific heat capacity of water) = 4200 J / (kg * ºС); t (boiling point of water) = 100 ºС.

The amount of heat: Q = (Ca * m1 + Cw * ρ * V2) * (t – t0).

Calculation: Q = (920 * 0.5 + 4200 * 1000 * 0.5 * 10-3) * (100 – 20) = 204 800 J (204.8 kJ).