0.5 mol of the H2SO4 solution was dipped into the glands. plate weighing 44.8 g, find the volume of gas that has formed.

Given:
n (H2SO4) = 0.5 mol
m (Fe) = 44.8 g

To find:
V (gas) -?

Decision:
1) H2SO4 + Fe => FeSO4 + H2 ↑;
2) n (Fe) = m (Fe) / M (Fe) = 44.8 / 56 = 0.8 mol;
3) n (H2) = n (H2SO4) = 0.5 mol;
4) V (H2) = n (H2) * Vm = 0.5 * 22.4 = 11.2 liters.

Answer: The volume of H2 is 11.2 liters.



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