1.0 g of some substance combines with 1.78 g of sulfur. Find the equivalent mass of the metal

1.0 g of some substance combines with 1.78 g of sulfur. Find the equivalent mass of the metal if the equivalent mass of sulfur is 16 g / mol.

Given:
m (Me) = 1.0 g
m (S) = 1.78 g
m eq (S) = 16 g / mol

Find:
m eq (Me) -?

Solution:
1) For the calculation, it is necessary to use the law of equivalents: the masses of the reacting and formed substances relate to each other as their equivalent masses;
2) m (Me) / m (S) = meq (Me) / meq (S);
3) m eq (Me) = m (Me) * m eq (S) / m (S) = 1.0 * 16 / 1.78 = 9 g / mol.

Answer: The equivalent mass of the metal is 9 g / mol.



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