1.12 L of methane (CH4) and 1.12 L of oxygen (O2) were mixed. How much carbon dioxide (CO2) is produced by the reaction?

Given:
V (CH4) = 1.12 L
V (O2) = 1.12 L

To find:
V (CO2) -?

Decision:
1) Write the reaction equation:
CH4 + 2O2 => CO2 + 2H2O;
2) Calculate the amount of CH4:
n (CH4) = V (CH4) / Vm = 1.12 / 22.4 = 0.05 mol;
3) Calculate the amount of substance O2:
n (O2) = V (O2) / Vm = 1.12 / 22.4 = 0.05 mol;
4) Determine the amount of substance CO2 (taking into account the coefficients in the reaction equation):
n (CO2) = n (O2) / 2 = 0.05 / 2 = 0.025 mol;
5) Calculate the volume of CO2:
V (CO2) = n (CO2) * Vm = 0.025 * 22.4 = 0.56 l.

Answer: The CO2 volume is 0.56 liters.



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