1.6 L of water was added to a solution of barium chloride weighing 2 kg with a mass fraction

1.6 L of water was added to a solution of barium chloride weighing 2 kg with a mass fraction of this salt equal to 18% (under normal conditions). Determine the mass fraction of barium chloride in the resulting solution.

1. Calculate the mass of barium chloride in the initial solution:

m (BaCl2) = w (BaCl2) * mout (solution) = 0.18 * 2000 = 360 g.

2. Considering that the density of water is 1 g / ml, we determine its mass:

m (H2O) = ρ * V = 1 * 1600 = 1600 g.

3. Find the mass of the resulting solution:

mpol (solution) = mout (solution) + m (H2O) = 2000 + 1600 = 3600 g.

4. Let’s calculate the mass fraction of barium chloride in the resulting solution:

wpol (BaCl2) = m (BaCl2): mpol (solution) = 360: 3600 = 0.1 or 10%.

Answer: 10%.