1.7 ethanol was obtained from ethylene with a mass of 20 g, what percentage is this of the theoretical yield.

To solve, we write the equation:
1. С2Н4 + Н2О = С2Н5ОН – hydration, ethyl alcohol is released;
2. Calculation of the molar masses of substances:
M (C2H4) = 28 g / mol;
M (C2H5OH) = 46 g / mol.
3. Determine the number of moles of ethylene by the formula:
Y (C2H4) = m / M = 20/28 = 0.714 mol;
Y (C2H5OH) = 0.714 mol since the amount of these substances is 1 mol, which confirms the equation.
4. Find the theoretical mass:
m (C2H5OH) = Y * M = 0.714 * 46 = 32.84 g.
5. Let’s make calculations using the formula:
W = m (practical) / m (theoretical) * 100;
W = 1.7 / 32.84 * 100 = 5.17%
Answer: the yield of the reaction product, ethanol, was 5.17%.