1.8 ∙ 10 ^ 4 tons of water falls from the dam 20 m high. What kind of work is being done?

To find the work done by the falling water, we will use the formula: A = F * S = m * g * h.

Constants and variables: m – the mass of the fallen water (m = 1.8 * 10 ^ 4 t = 1.8 * 10 ^ 7 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h – height of water fall (h = 20 m).

Let’s perform the calculation: A = m * g * h = 1.8 * 10 ^ 7 * 10 * 20 = 3.6 * 10 ^ 9 J = 3.6 GJ.

Answer: When 1.8 * 10 ^ 4 tons of water fall, work is performed at 3.6 GJ.