1-chloropropane obtained by hydrochlorination of 126 g of cyclopropane was heated

| May 8, 2021 | education

1-chloropropane obtained by hydrochlorination of 126 g of cyclopropane was heated with excess sodium. Find the mass of the hexane formed.

The reaction equation for the hydrochlorination of cyclopropane:

C3H6 + HCl = C3H7Cl

Amount of cyclopropane substance:

v (C3H6) = m (C3H6) / M (C3H6) = 126/42 = 3 (mol).

According to the reaction equation, from 1 mol of C3H6, 1 mol of C3H7Cl is formed, therefore:

v (C3H7Cl) = v (C3H6) = 3 (mol).

The equation for the reaction of 1-chloropropane with an excess of sodium (Wurtz reaction):

2C3H7Cl + 2Na = C6H14 + 2NaCl

According to the reaction equation, from 2 mol of C3H7Cl 1 mol of C6H14 is formed, therefore:

v (C6H14) = v (C3H7Cl) / 2 = 3/2 = 1.5 (mol),

and, then, the mass of the formed hexane:

m (C6H14) = v (C6H14) * M (C6H14) = 1.5 * 86 = 129 (g).

Answer: 129 g.



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