1 corner of a triangle is 3 times the other and 16 degrees more than the third. Find all the corners of the triangle.

Let the second angle of the triangle be x degrees, then the first angle of the triangle is 3x degrees, and the third angle of the triangle is (3x – 16) degrees. The sum of the angles of a triangle is (3x + x + (3x – 16)) degrees or 180 degrees. Let’s make an equation and solve it.

3x + x + (3x – 16) = 180;

3x + x + 3x – 16 = 180;

7x – 16 = 180;

7x = 180 + 16;

7x = 196;

x = 196: 7;

x = 28 ° – second angle;

3x = 28 * 3 = 84 ° – the first angle;

3x – 16 = 3 * 28 – 16 = 84 – 16 = 68 ° is the third angle.

Answer. 84 °, 28 °, 68 °.