1 kg of water taken at a temperature of 0 degrees Celsius was turned into 100 degree steam.

1 kg of water taken at a temperature of 0 degrees Celsius was turned into 100 degree steam. How much is the mass of steam more than the mass of water? Specific heat of water 4200 J / kg Specific heat of vaporization 2.3 * 10 ^ 6 J / kg

mw = 1 kg.

t = 100 “C.

C = 4200 J / kg * “C.

λ = 2.3 * 10 ^ 6 J / kg.

s = 3 * 10 ^ 8 m / s.

Δm -?

According to the law of equivalence of mass and energy, the following expression is valid: ΔE = Δm * c ^ 2, where ΔE is the change in the energy of water molecules, Δm is the change in the mass of water molecules, c is the speed of light.

Δm = ΔE / c ^ 2.

The energy of water molecules will increase by ΔE, which is determined by the formula: ΔE = m * (C * t + λ).

Δm = mw * (C * t + λ) / s ^ 2.

Δm = 1 kg * (4200 J / kg * “C * 100” C + 2.3 * 10 ^ 6 J / kg) / (3 * 10 ^ 8 m / s) ^ 2 = 0.3 * 10 ^ – 10 kg.

Answer: the mass of steam is greater than the mass of water by Δm = 0.3 * 10 ^ -10 kg.