1 mol of gas, at a pressure of 10 5 pa, is in a cylinder with a volume of 1 m3. Find the gas temperature.

We calculate the gas temperature using the equation of state for an ideal gas (Mendeleev – Clapeyron):

P * V = (m / M) * R * T, where P is the gas pressure (P = 10 ^ 5 Pa), V is the volume of the cylinder (V = 1 m3), m / M = υ is the amount of gas substance (υ = 1 mol), R is the universal gas constant (R = 8.31J / (mol * K)), T is the absolute temperature of the gas in the cylinder (K).

Let’s express and calculate the temperature:

T = P * V / (υ * R) = 10 ^ 5 * 1 / (1 * 8.31) = 12034 K.

Answer: The gas temperature is 12034 K.