10.7 g of ammonium chloride was mixed with calcium hydroxide and the mixture was heated.

10.7 g of ammonium chloride was mixed with calcium hydroxide and the mixture was heated. what gas and how much by mass and volume was released?

Given:
m (NH4Cl) = 10.7 g

To find:
gas -?
m (gas) -?
V (gas) -?

Decision:
1) 2NH4Cl + Ca (OH) 2 = (tOC) => CaCl2 + 2NH3 ↑ + 2H2O;
Gas NH3 – ammonia is evolved;
2) M (NH4Cl) = Mr (NH4Cl) = Ar (N) + Ar (H) * 4 + Ar (Cl) = 14 + 1 * 4 + 35.5 = 53.5 g / mol;
M (NH3) = Mr (NH3) = Ar (N) + Ar (H) * 3 = 14 + 1 * 3 = 17 g / mol;
3) n (NH4Cl) = m (NH4Cl) / M (NH4Cl) = 10.7 / 53.5 = 0.2 mol;
4) n (NH3) = n (NH4Cl) = 0.2 mol;
5) m (NH3) = n (NH3) * M (NH3) = 0.2 * 17 = 3.4 g;
6) V (NH3) = n (NH3) * Vm = 0.2 * 22.4 = 4.48 liters.

Answer: Gas – NH3 – ammonia; weight is 3.4 g; volume – 4.48 liters.