10.7 g of ammonium chloride was mixed with calcium hydroxide. What is the mass and volume of the evolved gas?

We write and equalize the reaction

2NH4Cl + Ca (OH) 2 = CaCl2 + 2NH3 + 2H2O

First, we find how many mol of ammonium chloride were taken:

n (NH4Cl) = m (NH4Cl) / M (NH4Cl)

We calculate the molar mass according to the periodic table:

M (NH4Cl) = 14 + 1 * 4 + 35.5 = 53.5 g / mol.

n (NH4Cl) = 10.7 / 53.5 = 0.2 mol.

Ammonium chloride and ammonia are the same amount, which means:

n (NH3) = n (NH4Cl) = 0.2 mol.

Mass: m (NH3) = n (NH3) * M (NH3) = 0.2 * (14 + 3) = 3.4 g.

Volume: V (NH3) = n (NH3) * Vm = 0.2 * 22.4 = 4.48 l.