10 g of sodium hydroxide solution with a mass fraction of 10% was added to 10 g of formic

10 g of sodium hydroxide solution with a mass fraction of 10% was added to 10 g of formic acid with W = 10%. Determine the mass of the resulting salt?

m (hcooh) = 10 * 0.1 = 1 g of pure acid

m (NaOH) = 10 * 0.1 = 1 g of pure alkali

HCOOH + NaOH = HCOONa + H20

n (hcooh) = 0.02 mol

m (salt) = 0.02 * 68 = 1.47 g



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