100 g of pure water was poured into a solution of sugar water weighing 200 g with a concentration

100 g of pure water was poured into a solution of sugar water weighing 200 g with a concentration of 30%. What is the concentration of sugar in the last solution?

Let’s solve this problem through the proportion:

1) (200 * 30%) / 100% = 60 (grams) – first found the mass of sugar in the solution.

2) 200 + 100 = 300 (gram) – calculated the mass of the new solution.

Let’s make the proportion:

300 grams – 100%;

60 grams – x;

Find x:

x = (60 g * 100%) / 300 g = 20% – the amount of sugar in the last solution.

Answer: 20%.