100 kg of water vapor at 100 C is passed through 1 ton of water at 0 C. To what temperature will the water be heated?
| May 9, 2021 | education
Given:
m (pair) = 100kg;
m (water) = 1000kg;
t (water) = 0 С;
L = 2260kJ;
To find:
t2 =?;
Decision:
Q1 = L * m + c * m * t;
Q2 = 2260000 * 100 + 4200 * 100 * 100 = 226000000 + 42000000 = 268000 kJ (This is how much energy was transferred to water).
Q3 = c * m * t;
268000000 = 4200 * 1000 * x;
x = 63.8 C;
Answer: 63.8 C;
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