10g of technical zinc reacts with HCe, 3.1l of H2 is released. Find W (impurities) in technical zinc.

1. Zinc has a high reactivity and, when interacting with an acid, displaces hydrogen from its composition, which describes the equation:

Zn + 2HCl = ZnCl2 + H2 ↑.

2. The volume of released hydrogen allows you to calculate its chemical amount:

n (H2) = V (H2): Vm = 3.1: 22.4 = 0.1384 mol.

3. The amount of moles of hydrogen will be proportional to the amount of zinc:

n (Zn) = n (H2) = 0.1384 mol.

4. Find the mass of zinc:

m (Zn) = n (Zn) * M (Zn) = 0.1384 * 65 = 8.996 g.

5. Determine the mass of impurities:

m (impurities) = m (tech. Zn) – m (Zn) = 10 – 8.996 = 1.004 g.

6. Set the mass fraction of impurities in the sample:

w (impurities) = m (impurities): m (tech. Zn) = 1.004: 10 = 0.1004 or 10.04%.

Answer: 10.04%.