11.2 iron interacts with 21.3 chlorine. Write the equation of the reaction.

11.2 iron interacts with 21.3 chlorine. Write the equation of the reaction. Calculate the mass fractions of chemical elements in the reaction product.

Fe + Cl2 = FeCl2;

Let’s find the amount of substance for the substances that have reacted. To do this, it is necessary to divide the mass of a substance by the molar mass of the same substance:

11.2 / 56 = 0.2 mol is the amount of iron;

21.3 / 70 = 0.3 mol is the amount of chlorine;

Chlorine is in excess. The amount of excess is 0.1 mol. We find the mass of the excess by multiplying the amount of substance by the molar mass:

0.1 * 71 = 7.1 grams;

The amount of iron is equal to the amount of the reaction product, since the reaction equation shows that they relate to each other as 1: 1.

Find the mass of the reaction product:

0.1 * 127 = 12.7;

Let’s find the mass fractions of substances. To do this, we divide the atomic mass of the element by the molar mass of the substance:

56/127 = 0.44 = 44% – iron content;

100 – 44 = 56% – chlorine content.