12 grams of magnesium oxide (MgO) reacts with hydrochloric acid (HCl), subtract the mass of the acid.

1) MgO + 2HCL = MgCL2 + H2O
2) calculate the amount of magnesium oxide substance
n (MgO) = m / M = 12g / 40 g / mol = 0.3 mol
3) n (MgO) = 2n (HCL) = 0.6 mol (since 1 mol of magnesium oxide consumes 2 mol of hydrochloric acid)
4) m (HCL) = M x n = 36.5 g / mol x 0.6 mol = 21.9 g
ANSWER: 21.9 g



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