12 grams of sodium hydroxide was chemically reacted with an aluminum bromide solution.

| July 6, 2021 | education

12 grams of sodium hydroxide was chemically reacted with an aluminum bromide solution. Determine the mass of the precipitate that is formed as a result of the reaction.

The mass of sodium hydroxide is 12 g.

Let us determine the mass of the precipitate obtained as a result of the reaction.

First, you need to write down the reaction equations and determine which precipitate was formed.

3NaOH + AlBr3 = 3NaBr + Al (OH) 3.

Consequently, as a result, a precipitate of aluminum hydroxide was formed. This means that it is necessary to determine the mass of the aluminum hydroxide precipitate.

First, let’s calculate the molar mass of sodium hydroxide.

M (NaOH) = 23 + 16 + 1 = 40 g / mol.

Let’s determine the molar mass of aluminum hydroxide.

M (Al (OH) 3) = 27 + 17 * 3 = 78 g / mol.

Determine the mass of the sediment.

12 g of sodium hydroxide – in g of aluminum hydroxide.

40 * 3 g / mol – 78 g / mol.

Y = 78 * 12 / (40 * 3) = 7.8 g.

Answer: the mass of aluminum hydroxide is 7.8 g.



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