120 g of a solution containing 10% sodium hydroxide NaOH absorb carbon dioxide CO2.

120 g of a solution containing 10% sodium hydroxide NaOH absorb carbon dioxide CO2. How many grams of sodium carbonate does this produce? (2NaOH + CO2 = Na2CO3 + H2O)

Let’s write the reaction equation:
2NaOH + CO2 = Na2CO3 + H2O
1. First, we find the mass of pure sodium hydroxide in the solution by the formula m (r.v.) = W * m (r.), Where m (r.v.) Is the mass of the solute, w is the mass fraction, m (r. ) – solution mass => m (NaOH) = 12 g
2. Now let’s calculate the amount of NaOH substance according to the formula n = m / M, where n is the amount of the substance, M is the molar mass (40 g / mol) => n = 0.3 mol
3. From the reaction equation n (Na2CO3) = 0.5n (NaOH) = 0.15 mol, then m (Na2CO3) = nM = 15.9 g
Answer: m (Na2CO3) = 15.9 g