120 g of sulfur was completely burned in oxygen. How much sulfur oxide (4) was produced?

Sulfur in oxygen burns with the formation of sulfur dioxide. The reaction equation is as follows:

S + O2 = SO2

To solve the problem, we first find the mass of sulfur oxide (IV).

Molar mass of sulfur = 32 g / mol; molar mass of sulfur dioxide = 64 g / mol

According to the reaction equation, we compose the proportion:

120 g of sulfur corresponds to X g of sulfur dioxide as

32 g / mol sulfur corresponds to 64 g / mol sulfur dioxide

X = (120 * 64) / 32 = 240 g of sulfur dioxide.

Knowing the mass, we calculate the amount of substance:

N = 240/64 = 3.75 mol

Now let’s calculate the volume using Avogadro’s law. Molar volume of gas = 22.4 l / mol.

V = 3.75 * 22.4 = 84 liters

Answer: volume of sulfur dioxide = 84 liters