128 g of SO2 was passed through 18 g of water. Determine the mass of the formed H2SO3.

Let’s compose the reaction equation:

SO2 + H2O = H2SO3;

According to the law of M.V. Lomonosov: “The mass of substances that have entered into a reaction is equal to the mass of substances formed in the course of this reaction.”

Therefore, the mass of H2SO4 is equal to the sum of the masses of SO2 and H2O:

m (H2SO4) = m (SO2) + m (H2O)

m (H2SO4) = 128 + 18 = 146 grams

Answer: 146 grams