128 grams of zinc dissolved in phosphoric acid find the volume of gas evolved.

The mass of zinc is equal to 128 g.

Let’s determine the volume of hydrogen that was formed as a result of the reaction.

First, you need to write down the reaction equations.

3Zn + 2H3PO4 = Zn3 (PO4) 2 + 3H2.

Determine the amount of zinc. We use the following formula to solve.

n = m / M.

Let’s calculate the molar mass.

M (Zn) = 65 g / mol.

n = 128/65 = 1.96 mol.

Further, according to the reaction equation, we determine the amount of hydrogen substance.

1.96 mol zinc – x mol hydrogen.

3 mol zinc – 3 mol hydrogen.

X = 3 * 1.96 / 3 = 1.96 mol.

Let’s determine the volume of hydrogen.

V = n * Vm = 1.96 * 22.4 = 44 liters.

Answer: the volume of hydrogen is 44 liters.