13.5 grams of zinc interact with hydrochloric acid. The volume fraction of hydrogen yield was 85%.

13.5 grams of zinc interact with hydrochloric acid. The volume fraction of hydrogen yield was 85%. Determine the amount of hydrogen released.

1. We write down the equation of the reaction of interaction of zinc with hydrochloric acid:

Zn + 2HCl = ZnCl2 + H2 ↑;

2.Calculate the theoretical chemical amount of zinc:

ntheor (Zn) = m (Zn): M (Zn) = 13.5: 65 = 0.2077 mol;

3. calculate the practical amount of hydrogen:

npract (H2) = ntheor (Zn) * ν = 0.2077 * 0.85 = 0.1765 mol;

4.determine the volume of released hydrogen:

V (H2) = npract (H2) * Vm = 0.1765 * 22.4 = 3.95 liters.

Answer: 3.95 liters.