13.8 g of potassium carbonate solution was mixed with 11.1 g of calcium chloride solution, bulk calcium carbonate

1. Find the amount of substance by the formula n = m / M.

a). М (К2СО3) = 39 × 2 + 12 + 16 × 3 = 138 g / mol, n (K2CO3) = 13.8 / 138 = 0.1 mol.

b). M (CaCl2) = 40 + 35.5 × 2 = 111 g / mol, n (CaCl2) = 11.1 / 111 = 0.1 mol.

Substances react in proportion to the coefficients, they are formed too.

K2CO3 + CaCl2 = CaCO3 + 2KCl

CaCO3 is also formed in an amount of 0.1 mol.

Find the mass: m = n × M. M (CaCO3) = 100 g / mol;

m (CaCO3) = 0.1 × 100 = 10 g.