13 g of zinc was dissolved in dilute chloride acid. How much hydrogen was released in this case?

The mass of zinc is 13 g.

Let us determine the volume of hydrogen obtained as a result of the reaction.

Let us write the equation for the reaction of the interaction of zinc with hydrochloric acid.

Zn + 2HCl = ZnCl2 + H2.

First, you should determine the amount of zinc. We use the following formula.

n = m / M.

Let’s determine the molar mass of zinc.

M (Zn) = 65 g / mol.

n = 13/65 = 0.2 mol.

Next, we will determine the amount of hydrogen substance obtained as a result of the reaction.

0.2 mol zinc – x mol oxygen.

1 mole of zinc – 1 mole of hydrogen.

X = 0.2 mol.

Let’s determine the volume of hydrogen.

V = n * Vm = 0.2 mol * 22.4 L / mol = 4.48 L.

Answer: the volume of hydrogen is 4.48 liters.