14 grams of calcium oxide (CaO) was treated with a nitric acid solution. How many grams of salt was formed?

Given:
m (CaO) = 14 g
To find:
m (Ca (NO3) 2)
Decision:
CaO + 2HNO3 = Ca (NO3) 2 + H2O
n (CaO) = m / M = 14 g / 56 g / mol = 0.25 mol
n (CaO): n (Ca (NO3) 2) = 1: 1
n (Ca (NO3) 2) = 0.25 mol
m (Ca (NO3) 2) = n * M = 0.25 mol * 164 g / mol = 41 g
Answer: 41 g



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