140 grams of lithium react with water. How many grams of hydrogen are released and how many grams of alkali are formed?

Lithium react with water.

2Li + 2H2O = 2LiOH + H2.

Let’s calculate the number of moles of substances taking into account the stoichiometric coefficients.

n (Li) = n • Mr = 140/2 • 7 = 10 mol.

n (LiOH) = n (Li) = 10 mol.

n (H2) = n (Li) / 2 = 10/2 = 5 mol.

The mass of the reaction products is.

m (LiOH) = n • Mr = 10 • 24 = 240 g.

m (H2) = n • Mr = 5 • 2 = 10 g.



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