15.5 g of phosphorus was burned, what is the volume of oxygen that reacted?

15.5 g of phosphorus was burned, what is the volume of oxygen that reacted? how much phosphorus oxide substance was formed?

The synthesis reaction of pentavalent phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. During the reaction, 2 molecules of pentavalent phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance contained in phosphorus weighing 15.5 grams.

M P = 31 grams / mol;

N P = 15.5 / 31 = 0.5 mol;

0.5 mol of phosphorus will react with 0.5 x 5/4 = 0.625 mol of oxygen.

Let’s calculate its volume.

To do this, multiply the amount of oxygen by the volume of 1 mole of gas.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V O2 = 0.625 x 22.4 = 14 liters;

In this case, 0.5 / 2 = 0.25 mol of phosphorus oxide will be synthesized.