15 g of ammonium chloride was mixed with 12 g of calcium hydroxide.

15 g of ammonium chloride was mixed with 12 g of calcium hydroxide. What gas and in what volume will be released as a result of the reaction?

Decision:
NH4Cl + Ca (OH) 2 = 2NH3 + CaCl2 + 2H2O
v (NH4Cl) = m / M = 15 / 53.5 = 0.28 mol
v (Ca (OH) 2) = m / M = 12/74 = 0.16 mol
v (Ca (OH) 2): v (NH3) = 1: 2
v (NH3) = 2 * 0.16 = 0.32 mol
V (NH3) = 0.32 * 22.4 = 7.168 l
Answer: V (NH3) = 7.168 l



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