15% solution has a mass of 800 grams. How much water needs to be removed to make it 20%?

Given:
ω1 (substances) = 15%
m1 solution (substance) = 800 g
ω2 (substances) = 20%

To find:
m (water) -?

Decision:
1) m1 (substances) = ω1 (substances) * m1 solution (substances) / 100% = 15% * 800/100% = 120 g;
2) m2 (substances) = m1 (substances) = 120 g;
3) m2 solution (substance) = m2 (substance) * 100% / ω2 (substance) = 120 * 100% / 20% = 600 g;
4) m (water) = m1 solution (substance) – m2 solution (substance) = 800 – 600 = 200 g.

Answer: The mass of water is 200 g.



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