150 g of a solution of 20% concentration of sulfuric acid interacts with a solution of barium chloride.

150 g of a solution of 20% concentration of sulfuric acid interacts with a solution of barium chloride. Determine the mass of the precipitate.

1. Let’s compose the equation of the proceeding reaction:

H2SO4 + BaCl2 = BaSO4 ↓ + 2HCl;

2. find the mass of sulfuric acid in the proposed solution:

m (H2SO4) = w (H2SO4) * m (solution) = 0.2 * 150 = 30 g;

3.Calculate the chemical amount of sulfuric acid:

n (H2SO4) = m (H2SO4): M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

n (H2SO4) = 30: 98 = 0.3 mol;

4. barium sulfate precipitated, we determine by the ratio of substances in the equation, its amount:

n (BaSO4) = n (H2SO4) = 0.3 mol;

5.Calculate the mass of the sediment:

m (BaSO4) = n (BaSO4) * M (BaSO4);

M (BaSO4) = 137 + 32 + 4 * 16 = 233 g / mol;

m (BaSO4) = 0.3 * 233 = 69.9 g.

Answer: 69.9 g.