156 g of benzene reacted with nitric acid. How many grams of nitrobenzene are formed?

1. The reaction of benzene with nitric acid is described by the equation:

C6H6 + 3HNO3 → C6H3 (NO2) 3 + 3H2O;

2. Let’s calculate the chemical amount of benzene:

n (C6H6) = m (C6H6): M (C6H6);

M (C6H6) = 6 * 12 + 6 = 78 g / mol;

n (C6H6) = 156: 78 = 2 mol;

3. The amounts of the reacted benzene and the formed nitrobenzene according to the equation are the same:

n (C6H3 (NO2) 3) = n (C6H6) = 2 mol;

4. Find the mass of nitrobenzene:

m (C6H3 (NO2) 3) = n (C6H3 (NO2) 3) * M (C6H3 (NO2) 3);

M (C6H3 (NO2) 3) = 6 * 12 + 3 + 3 * 14 + 2 * 3 * 16 = 213 g / mol;

m (C6H3 (NO2) 3) = 2 * 213 = 426 g.

Answer: 426 BC