15m3 of air has a temperature of 0 ° C. What will its volume become if it is heated by 17 ° C at a constant pressure.
| April 9, 2021 | education
If the pressure is constant, then we are talking about an isobaric process. In the isobaric process, the Gay-Lussac law is fulfilled, which has the form:
V1: T1 = V2: T2. Let us express the unknown quantity V2.
V2 = (V1 * T2): T1
It must be remembered that in such a section of physics as the MKT, the temperature is measured not in degrees Celsius, but in Kelvin. To find the temperature in Kelvin, add 273 to the temperature in Celsius. Since at first the temperature was equal to 0 ° C, then T1 = 0 ° C + 273 = 273 K. T2 = 17 ° C + 273 = 290 K. The volume V1 is known and is equal to 15 m³. Substitute the available values into the equation.
V2 = (15 m³ * 290 K): 273 K = 15.9 m³.
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