16 g of sulfur containing 7% impurities, burned. how many liters of sulfur dioxide were generated?
| May 23, 2021 | education
The reaction of the formation of sulfur dioxide is as follows:
S + O2 = SO2
For every mole of sulfur and oxygen reacting, 1 mole of sulfur (IV) oxide is released.
Let’s find the amount of sulfur that has reacted:
The mass of sulfur is 16 * (100 – 7)% / 100% = 16 * 0.93 = 14.88, and its amount is 14.88 / 32 = 0.465 mol.
The volume of SO2 obtained is 0.465 * 22.4 10.416 liters.
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