170 g of silver nitrate was mixed with sodium chloride to calculate the mass of the sediment.

Given:
m (AgNO3) = 170 g

To find:
m (draft) -?

Decision:
1) Reaction equation:
AgNO3 + NaCl => AgCl ↓ + NaNO3;
2) Molar masses:
M (AgNO3) = Mr (AgNO3) = Ar (Ag) * N (Ag) + Ar (N) * N (N) + Ar (O) * N (O) = 108 * 1 + 14 * 1 + 16 * 3 = 170 g / mol;
M (AgCl) = Mr (AgCl) = Ar (Ag) * N (Ag) + Ar (Cl) * N (Cl) = 108 * 1 + 35.5 * 1 = 143.5 g / mol;
3) Amount of substance:
n (AgNO3) = m (AgNO3) / M (AgNO3) = 170/170 = 1 mol;
4) Amount of substance:
n (AgCl) = n (AgNO3) = 1 mol;
5) Weight:
m (AgCl) = n (AgCl) * M (AgCl) = 1 * 143.5 = 143.5 g.

Answer: The mass of AgCl is 143.5 g.