2.2 liters of water was poured into the kettle at a temperature of 15 degrees.

2.2 liters of water was poured into the kettle at a temperature of 15 degrees. How much heat was required to obtain boiling water if 2 liters of water remained in the kettle after boiling.

The heat was spent on heating 2.2 kg of water to a temperature of 100 ° C and converting 0.2 kg of water into steam.

Heat balance equation:

Q = cm (t₁ – t) + rm₁,

where c is the specific heat capacity of water,

m is the mass of heated water,

m₁ is the mass of the formed steam,

t and t₁ are the initial and final temperatures,

r is the specific heat of vaporization.

Q = 4200 J / kg * deg * 2.2 kg * (100 ° C – 15 ° C) + 2260000 J / kg * 0.2 kg = 1 237 400 J.

Answer: 1,237,000 J (1,237 kJ).