2.24 liters of nitrogen with hydrogen form ammonia. find its mass, quantity and volume

Given:
V (N2) = 2.24 L

Find:
n (NH3) -?
m (NH3) -?
V (NH3) -?

Solution:
1) N2 + 3H2 => 2NH3;
2) M (NH3) = Mr (NH3) = Ar (N) + Ar (H) * 3 = 14 + 1 * 3 = 17 g / mol;
3) n (N2) = V (N2) / Vm = 2.24 / 22.4 = 0.1 mol;
4) n (NH3) = n (N2) * 2 = 0.1 * 2 = 0.2 mol;
5) m (NH3) = n (NH3) * M (NH3) = 0.2 * 17 = 3.4 g;
6) V (NH3) = n (NH3) * Vm = 0.2 * 22.4 = 4.48 liters.

Answer: The amount of NH3 substance is 0.2 mol; weight – 3.4 g; volume – 4.48 liters.