2.45 g of sulfuric acid, contained in the solution, reacted with zinc.

2.45 g of sulfuric acid, contained in the solution, reacted with zinc. Calculate the amount of hydrogen released. what is the mass of hydrogen formed from this.

Metallic zinc rapidly “dissolves” in sulfate acid, the reaction is described by the following chemical equation:

Zn + H2SO4 = ZnSO4 + H2;

Let’s find the molar amount of sulfuric acid.

To do this, we divide its weight by the weight of 1 mole of the substance.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 2.45 / 98 = 0.025 mol;

The reaction will release the same amount of hydrogen.

Let’s define the volume that it occupies.

To this end, we multiply the amount of substance by the volume of 1 mole of gas (assuming a volume of 22.4 liters).

V H2 = 0.025 x 22.4 = 0.56 liters;

Let’s calculate its weight.

To do this, multiply the amount of substance by the weight of 1 mole of hydrogen gas.

M H2 = 2 grams / mol;

m H2 = 2 x 0.025 = 0.05 grams;