2.47 * 10 ^ 19 electrons pass through a flashlight bulb in 8 seconds. What is the current in the light bulb?

n = 2.47 * 10 ^ 19 – the number of electrons passing through a flashlight bulb for a time interval t;

t = 8 seconds – time interval;

e = 1.6 * 10 ^ -19 Coulomb is the charge of one electron.

It is required to determine I (Ampere) – the current strength in a flashlight bulb.

Let’s find the total charge of the electrons that passed through the light bulb:

E = e * n = 1.6 * 10 ^ -19 * 2.47 * 10 ^ 19 = 1.6 * 2.47 = 4.4 Pendant.

Then the current strength will be equal to:

I = E / t = 4.4 / 8 = 0.55 Ampere.

Answer: The current in a flashlight bulb is 0.55 Amperes.