2.5 g of acetic acid was obtained from acetaldehyde weighing 2.2 g. Express this yield as a percentage

2.5 g of acetic acid was obtained from acetaldehyde weighing 2.2 g. Express this yield as a percentage of the theoretically possible.

CH3CHO + [O] = CH3COOH

1) Find the molecular weight of the aldehyde M (CH3CHO) = 2 * 12 + 16 + 4 * 1 = 48 g / mol.

2) Find the molecular weight of the acid M (CH3COOH) = 2 * 12 + 2 * 16 + 4 * 1 = 60 g / mol.

3) Find the theoretical yield of acid from 2.2 g of aldehyde.

Because aldehyde with acid are in a molecular ratio of 1: 1, then

from 48 g of aldehyde, 60 g of acid is obtained

from 2.2 g of aldehyde, X g of acid is obtained

x = 2.2 * 60/48 = 2.75 g – theoretical yield.

4) Express the practical yield as a percentage

2.75 g is 100%

2.5 g is X%

x = 2.5 * 100 / 2.75 = 90.9%.

Answer: 90.9%.