2 bodies move at the same speed, the path of 1 body is 10m. The path of the 2nd body is 0.02 km.

2 bodies move at the same speed, the path of 1 body is 10m. The path of the 2nd body is 0.02 km. Determine the time of movement of 2 bodies if the time of movement of 1 is 2 seconds.

To find the duration of the motion of the second indicated body, we will use the equality: S1 / t1 = V (the same speed of the two indicated bodies) = S2 / t2, whence we can express: t2 = t1 * S2 / S1.

Variables: t1 – duration of movement of the first specified body (t1 = 2 s); S2 is the path of the second body (S2 = 0.02 km = 20 m); S1 – path of the first body (S1 = 10 m).

Calculation: t2 = 2 * 20/10 = 4 s.

Answer: The second body indicated moved for 4 seconds.